## Precalculus: Mathematics for Calculus, 7th Edition

$3(x-1)(x+2)$
$Factor$ $the$ $expression$ $completely:$ $(x-1)(x+2)^2$ - $(x-1)^2(x+2)$ Factor out $(x-1)(x+2)$ from both terms $(x-1)(x+2)((x+2)-(x-1))$ Distribute the minus sign (-1) for $(x-1)$ in $((x+2)-(x-1))$ and simplify =$(x-1)(x+2)((x+2)+(-x+1))$ =$(x-1)(x+2)(x+2-x+1)$ =$(x-1)(x+2)(3)$ =$3(x-1)(x+2)$