Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 113

Answer

$(x+1)(x-1)(x+3)(x-3)$

Work Step by Step

$Factor$ $the$ $expression$ $completely:$ $x^2(x^2-1) - 9(x^2-1)$ Factor out $(x^2-1)$ from both terms $(x^2-1)(x^2-9)$ Use the Difference of Squares Formula for both binomials Difference of Squares Formula: $(A^2-B^2) = (A-B)(A+B)$ $(x^2-1) = (x+1)(x-1)$ $(x^2-9) = (x+3)(x-3)$ $= (x+1)(x-1)(x+3)(x-3)$
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