## Precalculus: Mathematics for Calculus, 7th Edition

$21t^{2}-26t+8$
First: $3t\times7t = 21t^{2}$ Outside: $3t\times-4 = -12t$ Inside: $-2\times7t =-14t$ Last: $-2\times-4 = 8$ Add the results from FOIL together: $=21t^{2}-12t-14t+8$ $=21t^{2}-26t+8$