Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 18

Answer

$(3x^{2}+x+1)-(2x^{2}-3x-5)=x^{2}+4x+6$

Work Step by Step

$(3x^{2}+x+1)-(2x^{2}-3x-5)$ Change the sign of the terms in the second parentheses and simplify by combining like terms: $(3x^{2}+x+1)-(2x^{2}-3x-5)=3x^{2}+x+1-2x^{2}+3x+5$ $...=x^{2}+4x+6$
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