Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 55

Answer

a)$2$ b)$-2$ c)$\frac{1}{3}$

Work Step by Step

a)$16^{\frac{1}{4}}=\sqrt[4] {16}=2$ b)$-8^{\frac{1}{3}}=\sqrt[3] {-8}=-2$ c)$9^{-1/2}=\frac{1}{9^{1/2}}=\frac{1}{\sqrt 9}=\frac{1}{3}$
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