Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 50

Answer

a)$8\sqrt 5$ b)$\sqrt[3] 2$

Work Step by Step

a)$\sqrt {125}+\sqrt {45}=\sqrt {25}\sqrt 5+\sqrt 9\sqrt 5=5\sqrt 5+3\sqrt 5=8\sqrt 5$ b)$\sqrt[3] {54}-\sqrt[3] {16}=\sqrt[3] {27}\sqrt[3] 2-\sqrt[3] 8\sqrt[3] 2=3\sqrt[3] 2-2\sqrt[3] 2=\sqrt[3] 2$
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