Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 45

Answer

a) $|x|$ b)$2x^{2}$

Work Step by Step

a)$\sqrt[4] {x^{4}}=|x|$ b)$\sqrt[4] {16x^{8}}=\sqrt[4] {16}\times\sqrt[4] {x^{8}}=\sqrt[4] {16}\times\sqrt[4] {{(x^{2})}^4}=2x^{2}$
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