## Precalculus: Mathematics for Calculus, 7th Edition

a) $\frac{x^7}{y}$ b) $\frac{a^9}{8b^6}$
a) $\frac{x^2y^{-1}}{x^-5}$ = $\frac{x^{2+5}}{y}$ = $\frac{x^7}{y}$ b) $(\frac{a^3}{2b^2})^3$ = $\frac{a^{(3)(3)}}{2^3b^{(2)(3)}}$ =$\frac{a^9}{8b^6}$