## Precalculus: Mathematics for Calculus, 7th Edition

a) $a^6$ b) $a^{18}$ c) $\frac{5x^9}{8}$
a) $\frac{a^{9}a^{-2}}{a}$ = $a^{9-2-1}$ = $a^{6}$ b) $(a^{2}$$a^{4})^3 = a^{(2+4)}$$^{3}$ = $a^{(6)}$$^{(3)} = a^{18} c) (\frac{x}{2})$$^3$(5$x^6$) = $\frac{x^3}{2^3}$(5$x^6$) = $\frac{5x^3x^6}{8}$ = $\frac{5x^{3+6}}{8}$ = $\frac{5x^{9}}{8}$