Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises: 25

Answer

a) $3$$\sqrt5$ b) 4 c) $6$$\sqrt[3] 2$

Work Step by Step

a) $\sqrt 3$$\sqrt 15$ = $\sqrt {3\times3\times5}$ = $\sqrt 9$$\sqrt 5$ = 3$\sqrt 5$ b) $\frac{\sqrt {48}}{\sqrt 3}$ = $\frac{\sqrt {3\times2\times8}}{\sqrt 3}$ = $\sqrt {16}$ = 4 c) $\sqrt[3]{24}$$\sqrt[3] {18}$= $\sqrt[3] {6^{3}\times2}$ = $6$$\sqrt[3] 2$
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