Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 24

Answer

a)$6\sqrt[3] 3$ b)$\frac{3\sqrt 2}{ 5}$ c)$\frac{2\sqrt 3}{7}$

Work Step by Step

a) $2\sqrt[3] {81}=2\times (9^{2})^{\frac{1}{3}}=2\times (3^{4})^{\frac{1}{3}}=6\sqrt[3] 3$ b) $\frac{\sqrt {18}}{\sqrt {25}}=\frac{\sqrt 9\times\sqrt 2}{\sqrt {25}}=\frac{3\sqrt 2}{ 5}$ c) $\sqrt {\frac{12}{49}}=\frac{\sqrt {4\times3}}{\sqrt {49}}=\frac{{\sqrt 4}\times\sqrt 3}{7}=\frac{2\sqrt 3}{7}$
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