Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises: 24

Answer

a)$6\sqrt[3] 3$ b)$\frac{3\sqrt 2}{\sqrt 5}$ c)$\frac{2\sqrt 3}{7}$

Work Step by Step

a)$2\sqrt[3] 81=2\times (9^{2})^{\frac{1}{3}}=2\times (3^{4})^{\frac{1}{3}}=6\sqrt[3] 3$ b)$\frac{\sqrt 18}{\sqrt 25}=\frac{\sqrt 9\times\sqrt 2}{\sqrt 25}=\frac{3\sqrt 2}{\sqrt 5}$ c)$\sqrt \frac{12}{49}=\frac{\sqrt {4\times3}}{\sqrt 49}=\frac{{\sqrt 4}\times\sqrt 3}{7}=\frac{2\sqrt 3}{7}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.