Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises: 23

Answer

a) $6$$\sqrt[3] 2$ b) $\frac{\sqrt 2}{3}$ c) $\frac{3\sqrt 3}{2}$

Work Step by Step

a) $3$$\sqrt[3] {16}$= $3$$\times$($4^{2}$)$^{1/3}$ = $3$$\times$($2^{4}$)$^{1/3}$ = $6$$\sqrt[3] 2$ b) $\frac{\sqrt {18}}{\sqrt {81}}$= $\frac{\sqrt 9 \times \sqrt 2}{\sqrt 9 \times \sqrt 9}$ = $\frac{\sqrt 2}{3}$ c) $\sqrt {\frac{27}{4}}$ = $\sqrt {\frac{9\times3}{4}}$ = $\frac{\sqrt 9 \times \sqrt3}{\sqrt4}$ = $\frac{3\sqrt 3}{2}$
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