Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises: 11

Answer

$\sqrt[3] (4^{2})$

Work Step by Step

$4^{2/3}$= ($4^{2}$)$^{1/3}$ = $\sqrt[3] (4^2)$
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