## Precalculus: Mathematics for Calculus, 7th Edition

By law 1: a$^{m}$ $\times$ a$^{n}$= a$^{n+m}$ So we have: 5$^{1/3}$ $\times$ 5$^{2/3}$= 5$^{\frac{1}{3}+ \frac{2}{3}}$ = 5$^{3/3}$ = 5.