## Precalculus: Mathematics for Calculus, 7th Edition

a) $5^{\frac{1}{3}}$ b) $\sqrt 5$ c) No. $\sqrt(25)$ = 5 =$\sqrt 5$ * $\sqrt 5$
a)$\sqrt[3] 5$ = $\sqrt[3]( 5^{1})$= $5^{\frac{1}{3}}$ b) $5^{\frac{1}{2}}$ = $\sqrt[2]( 5^{1})$ = $\sqrt 5$ c) Another way of looking at it with exponents: $\sqrt (5^{2})$ = ${{5^2}^{\frac{1}{2}}}$ = ${5^1}$ = 5 ${\sqrt 5}^{2}$= ${5^{\frac{1}{2}}}^{2}$ = 5