Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.11 - Solving Equations and Inequalities Graphically - 1.11 Exercises - Page 122: 46

Answer

$$x_1=0$$ $$x_2\approx0.01255$$

Work Step by Step

$x^3-6x^2+9x=\sqrt{x}$ To find the solution, we can graph the equations separated by the equal sign separately. $x^3-6x^2+9x$ is represented as the Blue graph on the image above. $\sqrt{x}$ is represented as the Red graph. (Note! the image above is zoomed-in near the origin of coordinate plane. Otherwise it is hard to notice the intersections, since it happens very close to $0$) The solutions are intersections of these graphs, those are the points $A$ and $B$. So we have another two solutions: $x_1=0$ $x_2\approx0.01255$
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