Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.11 - Solving Equations and Inequalities Graphically - 1.11 Exercises - Page 122: 40

Answer

$$x ∈[2.15, +\infty)$$ Also see the image below.

Work Step by Step

$(x+1)^2\leq x^3$ $(x+1)^2$ is represented as the Blue graph on the image above. $x^3$ is represented as the Red graph on the image above. We need to find the region, where the Blue graph is below the Red graph. That is the region from $A$ to $+\infty$. $x ∈[2.15, +\infty)$
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