Answer
$±4\sqrt 2$ $ \approx$ $±5.7$
Work Step by Step
Given equation is-
$x^{2}-32$ = $0$
Algebraic Solution:
$x^{2}$ = $32$
i.e. $x^{2}$ = $(±4\sqrt 2)^{2}$
i.e. $x$ = $±4\sqrt 2$
Graphical Solution:
$x^{2}-32$ = $0$
Now graphing $y$ = $x^{2}-32$
$x-intercepts$ are $+5.7$ and $-5.7$
i.e. $x$ = $+5.7$ and $-5.7$ are required solutions