Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.11 - Solving Equations and Inequalities Graphically - 1.11 Exercises - Page 121: 32

Answer

$x=-2.31$ and $1.79$

Work Step by Step

Given equation- $x^{4}$ = $ 16- x^{3}$ i.e. $x^{4} + x^{3}-16$ = $ 0$ We are asked to find a real solutions of this equation. Graphing y= $x^{4} + x^{3}-16$, using graphing calculator- We get two x−intercepts, i.e. $x=-2.3056$, and $x=1.79$ Therefore $x=-2.31$ and $1.79$ (Rounded to two decimals)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.