Answer
$x=-2.31$ and $1.79$
Work Step by Step
Given equation-
$x^{4}$ = $ 16- x^{3}$
i.e. $x^{4} + x^{3}-16$ = $ 0$
We are asked to find a real solutions of this equation.
Graphing y= $x^{4} + x^{3}-16$, using graphing calculator-
We get two x−intercepts, i.e. $x=-2.3056$, and $x=1.79$
Therefore $x=-2.31$ and $1.79$
(Rounded to two decimals)