Answer
$0$, and $3.31$
Work Step by Step
Given equation-
$x^{\frac{1}{2}} +x^{\frac{1}{3}} -x$ = $0$ , in the interval [-1,5]
We are asked to find all solutions 'x' that satisfy $-1 \leq x \leq 5$, so we use a graphing calculator to graph the equation in a viewing rectangle for which the x-values are restricted to the interval [-1,5] .
Graphing $y$ = $x^{\frac{1}{2}} +x^{\frac{1}{3}} -x$, using graphing calculator-
There are two $x-intercepts$ in the given interval, $x= 0$, and $3.31$
i.e. $x= 0$, and $3.31$