Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.10 - Lines - 1.10 Exercises - Page 115: 31

Answer

$y=-8x-11$ or, in general form, $8x+y+11=0$

Work Step by Step

Through $(-2,5)$ and $(-1,-3)$ Use the point-slope form of the equation of a line, which is $y-y_{1}=m(x-x_{1})$, where $(x_{1},y_{1})$ is a point through which the line passes and $m$ is the slope. Two point through which the lines passes are given. Use them to fin de the slope of the line: $m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}=\dfrac{-3-5}{-1-(-2)}=\dfrac{-8}{-1+2}=\dfrac{-8}{1}=-8$ Substitute $m$ and whichever of the points given into the formula and simplify to obtain the equation of this line: $y-y_{1}=m(x-x_{1})$ $y-5=-8(x+2)$ $y-5=-8x-16$ $y=-8x-16+5$ $y=-8x-11$ or, in general form, $8x+y+11=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.