Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.10 - Lines - 1.10 Exercises - Page 115: 30

Answer

$y=x-1$ or, in general form, $x-y-1=0$

Work Step by Step

Through $(-1,-2)$ and $(4,3)$ Use the point-slope form of the equation of a line, which is $y-y_{1}=m(x-x_{1})$, where $(x_{1},y_{1})$ is a point through which the line passes and $m$ is the slope. Two point through which the line passes are given. Use them to find the slope of the line: $m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}=\dfrac{3-(-2)}{4-(-1)}=\dfrac{5}{5}=1$ Substitute $m$ and whichever of the given points into the formula and simplify to obtain the equation of this line: $y-y_{1}=m(x-x_{1})$ $y-3=(1)(x-4)$ $y-3=x-4$ $y=x-4+3$ $y=x-1$ or, in general form, $x-y-1=0$
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