Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.10 - Lines - 1.10 Exercises - Page 114: 28

Answer

$y=-\dfrac{7}{2}x-\dfrac{31}{2}$ or, in general form, $7x+2y+31=0$

Work Step by Step

Through $(-3,-5);$ slope $-\frac{7}{2}$ Use the point-slope form of the equation of a line, which is $y-y_{1}=m(x-x_{1})$, where $(x_{1},y_{1})$ is a point through which the line passes and $m$ is the slope. Both $m$ and $(x_{1},y_{1})$ are given. Substitute them into the formula and simplify to obtain the equation of this line: $y-y_{1}=m(x-x_{1})$ $y+5=-\dfrac{7}{2}(x+3)$ $y+5=-\dfrac{7}{2}x-\dfrac{21}{2}$ $y=-\dfrac{7}{2}x-\dfrac{21}{2}-5$ $y=-\dfrac{7}{2}x-\dfrac{31}{2}$ or, in general form, $7x+2y+31=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.