## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises: 81

#### Answer

$|a-b|=b-a$

#### Work Step by Step

$|a-b|,$ where $a\lt b$ The problem specifies that $a\lt b$. This means that the substraction inside the absolute value bars will result in a negative number. To express this quantity without using absolute value, we must change its sign: $|a-b|=-(a-b)=b-a$

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