Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises: 75

Answer

$x=\pm4i$

Work Step by Step

$x^{2}+16=0$ Take $16$ to the right side: $x^{2}=-16$ Take the square root of both sides: $\sqrt{x^{2}}=\sqrt{-16}$ $x=\pm4i$
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