## Precalculus: Mathematics for Calculus, 7th Edition

$x=11$ and $x=3$
$|x-7|=4$ By the definition of absolute value, solving this equation is equivalent to solving two separate equations, which are: $x-7=4$ and $x-7=-4$ Solve both equations for $x$: $x-7=4$ $x=4+7$ $x=11$ $x-7=-4$ $x=-4+7$ $x=3$