Answer
$\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}=-\dfrac{1}{2x}$
Work Step by Step
$\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}$
Evaluate the sum of fractions in the numerator:
$\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}=\dfrac{\dfrac{2-x}{2x}}{x-2}=...$
Evaluate the division:
$...=\dfrac{2-x}{2x}\div(x-2)=\dfrac{2-x}{2x(x-2)}=...$
Simplify:
$...=-\dfrac{x-2}{2x(x-2)}=-\dfrac{1}{2x}$