Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises: 47

Answer

$\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}=-\dfrac{1}{2x}$

Work Step by Step

$\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}$ Evaluate the sum of fractions in the numerator: $\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}=\dfrac{\dfrac{2-x}{2x}}{x-2}=...$ Evaluate the division: $...=\dfrac{2-x}{2x}\div(x-2)=\dfrac{2-x}{2x(x-2)}=...$ Simplify: $...=-\dfrac{x-2}{2x(x-2)}=-\dfrac{1}{2x}$
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