Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises: 34

Answer

$\dfrac{(x-1)(x-7)}{x^{3/2}}$ or $\dfrac{(x-1)(x-7)}{\sqrt{x^{3}}}$ or $x^{-3/2}(x-1)(x-7)$

Work Step by Step

$7x^{-3/2}-8x^{-1/2}+x^{1/2}$ Take out common factor $x^{-3/2}$: $7x^{-3/2}-8x^{-1/2}+x^{1/2}=x^{-3/2}(7-8x+x^{2})=...$ Rearrange: $...=x^{-3/2}(x^{2}-8x+7)=...$ Factor the expression inside the parentheses: $...=x^{-3/2}(x-1)(x-7)=...$ Rearrange again: $...=\dfrac{(x-1)(x-7)}{x^{3/2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.