## Precalculus: Mathematics for Calculus, 7th Edition

$2y^2(y+2)(y-2)(y^2+4)$
$Factor$ $the$ $expression$ $completely:$ $2y^6-32y^2$ Factor out $2y^2$ $2y^2(y^4-16)$ Use the Difference of Squares Formula $2y^2(y^4-16) = 2y^2(y^2-4)(y^2+4)$ Use the Difference of Squares Formula for $y^2-4$ $2y^2(y^2-4)(y^2+4) = 2y^2(y+2)(y-2)(y^2+4)$