## Precalculus: Mathematics for Calculus, 7th Edition

$$2(2x-1)(3x+4)$$
$Factor$ $the$ $expression$ $completely:$ $12x^2+10x-8$ Factor out a 2 $2(6x^2+5x-4)$ Factor the trinomial into binomials [Note: The signs are plus then minus, so there must be a addition parenthesis times a subtraction parenthesis] $$6x^2+5x-4 = (2x-1)(3x+4)$$ $$2(2x-1)(3x+4)$$ Check: Use the FOIL Method $2x\times 3x = 6x^2$ $2x\times4 = 8x$ $-1\times3x = -3x$ $-1\times 4 = -4$ $2(6x^2+8x-3x-4) = 2(6x^2+5x-4)$ $=12x^2+10x-8$