Answer
$$2(2x-1)(3x+4)$$
Work Step by Step
$Factor$ $the$ $expression$ $completely:$
$12x^2+10x-8$
Factor out a 2
$2(6x^2+5x-4)$
Factor the trinomial into binomials [Note: The signs are plus then minus, so there must be a addition parenthesis times a subtraction parenthesis]
$$6x^2+5x-4 = (2x-1)(3x+4)$$
$$2(2x-1)(3x+4)$$
Check:
Use the FOIL Method
$2x\times 3x = 6x^2$
$2x\times4 = 8x$
$-1\times3x = -3x$
$-1\times 4 = -4$
$2(6x^2+8x-3x-4) = 2(6x^2+5x-4)$
$=12x^2+10x-8$