## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 1 - Review - Exercises: 25

#### Answer

$$(x+7)(x-2)$$

#### Work Step by Step

$Factor$ $the$ $expression$ $completely:$ $x^2+5x-14$ Factor [Note: We notice that there is a plus then a minus, so we must have an addition parenthesis times a subtraction parenthesis] $$(x+7)(x-2)$$ Check: Use the FOIL Method for $(x+7)(x-2)$ $x\times x = x^2$ $x\times -2 = -2x$ $7\times x = 7x$ $7\times -2 = -14$ $x^2-2x+7x-14 = x^2+5x-14$

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