Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises: 19

Answer

$a)$ $x^{2}y^{2}$ $b)$ $xy^{2}$

Work Step by Step

$a)$ $\sqrt[3]{(x^{3}y)^{2}y^{4}}$ Evaluate the power inside the root: $\sqrt[3]{(x^{3}y)^{2}y^{4}}=\sqrt[3]{(x^{6}y^{2})y^{4}}=...$ Evaluate the product inside the root: $...=\sqrt[3]{x^{6}y^{2+4}}=\sqrt[3]{x^{6}y^{6}}=...$ Evaluate the root: $...=x^{2}y^{2}$ $b)$ $\sqrt{x^{2}y^{4}}$ Evaluate the square root: $\sqrt{x^{2}y^{4}}=xy^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.