Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises: 14



Work Step by Step

$Evaluate$ $the$ $expression:$ $$64^\frac{2}{3}$$ $$64^\frac{2}{3} = (\sqrt [3] {64})^2$$ $$(\sqrt [3] {64})^2 = 4^2$$ $$=16$$
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