Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Concept Check - Page 132: 12

Answer

To solve $$x^{2}-9$$ Let’s use difference of squares $$(a+3)(a-3)$$

Work Step by Step

SPECIAL FACTORING FORMULAS Difference of squares $$(a^{2}-b^{2})=(a+b)(a-b)$$ Perfect squares $$ (a+b)^{2}=(a^{2}+2ab+b^{2}$$ Sum of Cubes $$(a^{3}+b^{3})= (a+b)(a^{2}-ab+b^{2})$$ $$x^{2}-9$$ Let’s use difference of squares $$(a+3)(a-3)$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.