Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

We use the general equation of a line to find an equation for this specific line. The general equation of a line is $y - y_{1} = m(x - x_{1})$. The line must have slope $m = 2$. The line must also pass through the point (4, -3) which are our $x_{1}$ and $y_{1}$. Putting this information into the general equation of a line, we get $y + 3 = 2(x - 4)$. We distribute $2$ to get $y + 3 = 2x -8$ Then, we subtract 3 from each side to get $y= 2x -11$