Answer
0.
Work Step by Step
$sin40^\circ+sin130^\circ+sin220^\circ+sin310^\circ\\
=sin40^\circ+sin(180-50)^\circ+sin(180+40)^\circ+sin(360-50)^\circ\\
=sin40^\circ+sin50^\circ-sin40^\circ-sin50^\circ\\
=0$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 87
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