Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 86

Answer

$\frac{2\sqrt 3}{3}$

Work Step by Step

$tan60^\circ+tan150^\circ\\ =tan60^\circ+tan(180-30)^\circ\\=tan60^\circ-tan30^\circ\\ =\sqrt 3-\frac{\sqrt 3}{3}\\ =\frac{2\sqrt 3}{3}$
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