Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 81

Answer

1. $sin(\theta)= -\frac{\sqrt {2}}{2}$. 2. $cos(\theta)= -\frac{\sqrt {2}}{2}$. 3. $tan(\theta)= 1$. 4. $cot(\theta)= 1$. 5. $sec(\theta)= -\sqrt 2$. 6. $csc(\theta)= -\sqrt 2$.

Work Step by Step

Given point $(-2,-2)$, we have $x=-2, y=-2, r=\sqrt {(-2)^2+(-2)^2}=2\sqrt {2}$, we have: 1. $sin(\theta)= \frac{y}{r}= -\frac{2}{2\sqrt {2}}=-\frac{\sqrt {2}}{2}$. 2. $cos(\theta)= \frac{x}{r}= \frac{-2}{2\sqrt {2}}=-\frac{\sqrt {2}}{2}$. 3. $tan(\theta)= \frac{y}{x}=\frac{-2}{-2}=1$. 4. $cot(\theta)=\frac{1}{tan(\theta)}=1$. 5. $sec(\theta)=\frac{1}{cos(\theta)}=-\sqrt 2$. 6. $csc(\theta)=\frac{1}{sin(\theta)}=-\sqrt 2$.
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