Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 80

Answer

1. $sin(\theta)= -\frac{2\sqrt {5}}{5}$. 2. $cos(\theta)= -\frac{\sqrt {5}}{5}$. 3. $tan(\theta)= 2$. 4. $cot(\theta)= \frac{1}{2}$. 5. $sec(\theta)= -\sqrt 5$. 6. $csc(\theta)= -\frac{\sqrt {5}}{2}$.

Work Step by Step

Given point $(-1,-2)$, we have $x=-1, y=-2, r=\sqrt {(-1)^2+(-2)^2}=\sqrt {5}$, we have: 1. $sin(\theta)= \frac{y}{r}= -\frac{2}{\sqrt {5}}=-\frac{2\sqrt {5}}{5}$. 2. $cos(\theta)= \frac{x}{r}= \frac{-1}{\sqrt {5}}=-\frac{\sqrt {5}}{5}$. 3. $tan(\theta)= \frac{y}{x}=\frac{-2}{-1}=2$. 4. $cot(\theta)=\frac{1}{tan(\theta)}=\frac{1}{2}$. 5. $sec(\theta)=\frac{1}{cos(\theta)}=-\sqrt 5$. 6. $csc(\theta)=\frac{1}{sin(\theta)}=-\frac{\sqrt {5}}{2}$.
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