Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 58

Answer

1. $sin(-\frac{\pi}{3})= -\frac{\sqrt 3}{2}$. 2. $cos(-\frac{\pi}{3})= \frac{1}{2}$. 3. $tan(-\frac{\pi}{3})= -\sqrt 3$. 4. $cot(-\frac{\pi}{3})= -\frac{\sqrt 3}{3}$. 5. $sec(-\frac{\pi}{3})= 2$. 6. $csc(-\frac{\pi}{3})= -\frac{2\sqrt 3}{3}$.

Work Step by Step

1. $sin(-\frac{\pi}{3})=-sin(\frac{\pi}{3})=-\frac{\sqrt 3}{2}$. 2. $cos(-\frac{\pi}{3})=cos(\frac{\pi}{3})=\frac{1}{2}$. 3. $tan(-\frac{\pi}{3})=-tan(\frac{\pi}{3})=-\sqrt 3$. 4. $cot(-\frac{\pi}{3})=\frac{1}{tan(-\frac{\pi}{3})}=-\frac{\sqrt 3}{3}$. 5. $sec(-\frac{\pi}{3})=\frac{1}{cos(-\frac{\pi}{3})}=2$. 6. $csc(-\frac{\pi}{3})=\frac{1}{sin(-\frac{\pi}{3})}=-\frac{2\sqrt 3}{3}$.
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