Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 50

Answer

1. $sin240^\circ= -\frac{\sqrt 3}{2}$. 2. $cos240^\circ= -\frac{1}{2}$. 3. $tan240^\circ= \sqrt 3$. 4. $cot240^\circ= \frac{\sqrt 3}{3}$. 5. $sec240^\circ= -2$. 6. $csc240^\circ= -\frac{2\sqrt 3}{3}$.

Work Step by Step

1. $sin240^\circ=sin(180+60)^\circ=-sin60^\circ=-\frac{\sqrt 3}{2}$. 2. $cos240^\circ=cos(180+60)^\circ=-cos60^\circ=-\frac{1}{2}$. 3. $tan240^\circ=tan(180+60)=tan60^\circ=\sqrt 3$. 4. $cot240^\circ=\frac{1}{tan240^\circ}=\frac{\sqrt 3}{3}$. 5. $sec240^\circ=\frac{1}{cos240^\circ}=-2$. 6. $csc240^\circ=\frac{1}{sin240^\circ}=-\frac{2\sqrt 3}{3}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.