Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.2 Trigonometric Functions: Unit Circle Approach - 5.2 Assess Your Understanding - Page 403: 103

Answer

$\sqrt 3$

Work Step by Step

Let us consider: $f(\theta)=\sin \theta$ and $\theta=60^{\circ}$ We know from the unit circle that $\sin (60^{\circ})=\sin (\dfrac{\pi}{3})=\dfrac{\sqrt 3}{2}$ Thus, we have: $ 2 \ f (\theta)= 2 \times \sin (60^{\circ}) \\=2 \times \sin (\dfrac{\pi}{3}) \\ = 2 \times \dfrac{\sqrt 3}{2} \\=\sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.