## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$3^{-2}=\frac{1}{9}$
RECALL: $\log_b{x}=y \longrightarrow b^y=x$ Use the rule above to obtain: $\log_3{(\frac{1}{9})}=-2 \longrightarrow 3^{-2}=\frac{1}{9}$