Answer
$\displaystyle \frac{1}{9}$
Work Step by Step
Apply rule $\quad a^{m}\cdot a^{n}=a^{m+n}$:
$3^{-6}\cdot 3^{4}=3^{-6+4}=3^{-2}$
Apply rule $\displaystyle \quad a^{-n}=\frac{1}{a^{n}}$:
$=\displaystyle \frac{1}{3^{2}}$
$=\displaystyle \frac{1}{9}$
