Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding: 55

Answer

$0$

Work Step by Step

Substitute the given values of the variables into the expression: $\dfrac {3x+2y}{2+y}=\dfrac {3\times \left( -2\right) +2\times 3}{2+3}=\dfrac {-6+6}{5}=\dfrac {0}{5}=0$
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