Answer
$ 2\sqrt {2x}$
Work Step by Step
$\sqrt {32x}+\sqrt {2x}-\sqrt {18x}=\sqrt {4^2\cdot 2x}+\sqrt {2x}-\sqrt {3^2\cdot 2x}=4\sqrt {2x}+\sqrt {2x}-3\sqrt {2x}=2\sqrt {2x}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - Test - Page 86: 26
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