Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 86: 25

Answer

$3x^2y^4\sqrt {2x}$

Work Step by Step

$\sqrt {18x^5y^8}=\sqrt {2\cdot 3^2 x\cdot x^4\cdot (y^4)^2}=3x^2y^4\sqrt {2x}$
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