Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Test - Page 86: 24

Answer

$\frac{y}{y+2}$

Work Step by Step

Multiply $y$ to both the numerator and the denominator, we have $\frac{y-2}{y-\frac{4}{y}}=\frac{y-2}{y-\frac{4}{y}}\times\frac{y}{y}=\frac{y(y-2)}{y^2-4}=\frac{y(y-2)}{(y+2)(y-2)}=\frac{y}{y+2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.