Answer
$\frac{1+2x^3-2x}{4}$
Work Step by Step
Start with cancelling the common factor $4(x^2-1)^3$, we have:
$\frac{4(x^2-1)^3+8x(x^2-1)^4}{16(x^2-1)^3}=\frac{1+2x(x^2-1)}{4}=\frac{1+2x^3-2x}{4}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises - Page 65: 113
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