Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.6 Rational Exponents - R.6 Exercises: 82

Answer

$\color{blue}{9p^6+3p^3}$

Work Step by Step

RECALL: (1) $a(b+c) = ab + ac$ (2) $a^m \cdot a^n = a^{m+n}$ Use rule (1) above to obtain: $=p^{11/5} \cdot 3p^{4/5} +p^{11/5} \cdot 9p^{19/5}$ Use rule (2) above to obtain: $=3p^{11/5+4/5} + 9p^{11/5+19/5} \\=3p^{15/5} + 9p^{30/5} \\=3p^3 +9p^6 \\=\color{blue}{9p^6+3p^3}$
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